What the question is asking

The wording used in MATH 200 questions, and what it wants you to do.

Points and vectors

“Describe the set of all points (x,y,z)(x, y, z) in R3\mathbb R^3 that satisfy …”
Complete the square and name the shape, like "the sphere of radius rr centered at …". With <<, it is the inside of the sphere.Vectors →
“Determine whether or not the given points are collinear”
Collinear means on one line: AC→\overrightarrow{AC} is a multiple of AB→\overrightarrow{AB}.AC→=c AB→\overrightarrow{AC} = c\,\overrightarrow{AB}Vectors →
“Find the component of b\mathbf b in the direction a\mathbf a”
A number, not a vector: how far b\mathbf b reaches along a\mathbf a.a⋅b∣a∣\dfrac{\mathbf a\cdot\mathbf b}{|\mathbf a|}Vectors →
“Compute the volumes of the parallelepipeds determined by the following vectors”
It is the slanted box with the three vectors as edges from one corner. Take the triple product and drop its sign.∣a⋅(b×c)∣|\mathbf a\cdot(\mathbf b\times\mathbf c)|Vectors →

Lines, planes and curves

“Find the vector parametric, scalar parametric and symmetric equations for the line”
One line, written three ways. Vector: ⟨x,y,z⟩=P+t d\langle x, y, z\rangle = P + t\,\mathbf d. Scalar: x=x0+d1tx = x_0 + d_1t, and so on. Symmetric: solve each for tt and set them equal.Lines →
“the line of intersection of the given planes / the line through … and parallel to each of the two planes”
Either way, the direction is perpendicular to both normals, so cross them. For the intersection, also find one point on both planes.d=n1×n2\mathbf d = \mathbf n_1\times\mathbf n_2Lines →
“the plane containing AA and perpendicular to LL”
The line's direction is the plane's normal.n=dL\mathbf n = \mathbf d_LPlanes →
“the plane PP that contains L1L_1 and is parallel to L2L_2”
Both directions lie along the plane, so their cross product is the normal. Use a point of L1L_1.n=d1×d2\mathbf n = \mathbf d_1\times\mathbf d_2Planes →
“the unit tangent vector … pointing in the direction of increasing tt”
Use +r′(t)+\mathbf r'(t) (not its negative) and divide by its length.T^=r′(t)∣r′(t)∣\hat{\mathbf T} = \dfrac{\mathbf r'(t)}{|\mathbf r'(t)|}Curves →
“the particle flies off the path on a line LL in the direction tangent to the path”
It continues along the tangent line at that moment: r(t0)+u r′(t0)\mathbf r(t_0) + u\,\mathbf r'(t_0).Curves →

Surfaces and level curves

“Draw a contour map of …, showing all types of level curves that occur”
Draw the curves f(x,y)=cf(x, y) = c in the xyxy-plane. Split into cases of cc, often c>0c > 0, c=0c = 0 and c<0c < 0. Label at least one curve of each type.f(x,y)=cf(x, y) = cSurfaces →
“Describe the level surfaces of f(x,y,z)f(x, y, z)”
Name the surface f(x,y,z)=cf(x, y, z) = c for each case of cc, including empty cases and single points.f(x,y,z)=cf(x, y, z) = cSurfaces →
“Sketch and describe the following surfaces”
Slice across and along the axis, name the surface, and give its axis, center or vertex.Surfaces →

Limits and partial derivatives

“Evaluate each of the following limits or show that it does not exist”
First try plugging in. If that fails, simplify or use polar coordinates to find the value. Or find two paths that give different limits.Limits & Continuity →
“Express the function in terms of the polar coordinates rr and θ\theta, and simplify”
Substitute x=rcos⁡θx = r\cos\theta, y=rsin⁡θy = r\sin\theta and cancel powers of rr.x=rcos⁡θ, y=rsin⁡θx = r\cos\theta,\ y = r\sin\thetaLimits & Continuity →
“Compute, directly from the definitions”
Use the limit of the difference quotient, not the derivative rules. The rules usually fail at that special point.fx(a,b)=lim⁡h→0f(a+h,b)−f(a,b)hf_x(a, b) = \lim_{h\to 0}\dfrac{f(a + h, b) - f(a, b)}{h}Partial Derivatives →
“Find all first partial derivatives of the following functions and evaluate them at the given point”
Find one partial per variable, holding the other variables constant. Plug in the point last.Partial Derivatives →
“A surface z(x,y)z(x, y) is defined by … Compute ∂z∂x\dfrac{\partial z}{\partial x}, ∂z∂y\dfrac{\partial z}{\partial y} in terms of xx, yy, zz”
Implicit differentiation: differentiate both sides, treating zz as a function of xx and yy.∂z∂x=−FxFz\dfrac{\partial z}{\partial x} = -\dfrac{F_x}{F_z}Partial Derivatives →
“Which of the following functions are harmonic?”
Harmonic means it solves Laplace's equation: check uxx+uyy=0u_{xx} + u_{yy} = 0 everywhere uu is defined.uxx+uyy=0u_{xx} + u_{yy} = 0Partial Derivatives →

Chain rule

“Write out the chain rule for each of the following functions”
Draw the . Write one product per path, and show where each partial is evaluated.Chain Rule →
“You may assume that ff is a smooth function so that the Chain Rule and Clairaut's Theorem … apply”
This is a second-derivative chain rule question. f1f_1 is the partial in ff's first slot. f12f_{12} is first slot, then second. You may combine f12f_{12} and f21f_{21} into one term.f12=f21f_{12} = f_{21}Chain Rule →
“For an arbitrary F(z)F(z) show that u(x,y)u(x, y) satisfies …”
FF has no formula: keep F′F' (or FuF_u, FvF_v) as a symbol and show the equation holds anyway.Chain Rule →

Tangent planes and normal lines

“Find the tangent plane and normal line to the surface … at …”
Find a normal vector n\mathbf n at the point. The plane is n⋅⟨x−x0,y−y0,z−z0⟩=0\mathbf n \cdot \langle x - x_0, y - y_0, z - z_0\rangle = 0. The line is the point plus t nt\,\mathbf n.⟨x0,y0,z0⟩+t n\langle x_0, y_0, z_0\rangle + t\,\mathbf nTangent Planes →
“Use a 3-dimensional gradient vector to find the equation of the tangent plane”
Write the surface as F(x,y,z)=cF(x, y, z) = c and use ∇F\nabla F at the point as the normal.n=∇F(x0,y0,z0)\mathbf n = \nabla F(x_0, y_0, z_0)Tangent Planes →
“where the tangent plane is parallel to the plane …”
The surface's normal is a multiple of the plane's normal: solve ∇F=λ n\nabla F = \lambda\,\mathbf n with the surface equation.∇F=λ n\nabla F = \lambda\,\mathbf nTangent Planes →
“Find all horizontal planes that are tangent to the surface”
Horizontal means normal ⟨0,0,1⟩\langle 0, 0, 1\rangle: on z=f(x,y)z = f(x, y), solve fx=0f_x = 0 and fy=0f_y = 0.fx=fy=0f_x = f_y = 0Tangent Planes →
“tangent to the curve of intersection of the surfaces …”
The curve's direction is perpendicular to both normals: cross the two gradients.∇F×∇G\nabla F \times \nabla GTangent Planes →

Linear approximation and error

“Find an approximate value … without using a calculator or computer”
Use the linear approximation at a nearby point where ff is easy to compute.f(a,b)+fx Δx+fy Δyf(a, b) + f_x\,\Delta x + f_y\,\Delta yLinear Approximation →
“Use differentials to …”
Estimate a change with df=fx dx+fy dydf = f_x\,dx + f_y\,dy: each partial times its own small change.df=fx dx+fy dydf = f_x\,dx + f_y\,dyLinear Approximation →
“estimate the maximum possible error in calculating …”
Add the absolute value of each error's contribution, so nothing cancels.∣fx∣ Δx+∣fy∣ Δy|f_x|\,\Delta x + |f_y|\,\Delta yLinear Approximation →
“find the approximate percentage error in calculating …”
The maximum error divided by the value, times 100100.100 ∣Δf∣∣f∣100\,\dfrac{|\Delta f|}{|f|}Linear Approximation →
“near this point the surface determines xx as a function … of yy and zz”
xx is the dependent variable. Differentiate implicitly in yy and in zz to get xyx_y and xzx_z.Linear Approximation →

Directional derivatives and the gradient

“Find the rate of change of the given function at the given point in the given direction”
The directional derivative: dot the gradient with the unit vector of the direction.Duf=∇f⋅uD_{\mathbf u}f = \nabla f \cdot \mathbf uGradient →
“In what direction should the hiker proceed from PP to ascend along the steepest path?”
Along ∇f\nabla f. The slope of that path is ∣∇f∣|\nabla f|.∇f, ∣∇f∣\nabla f,\ |\nabla f|Gradient →
“Find the maximum rate of change of f(x,y)f(x, y) at the point …”
The length of the gradient there.∣∇f∣|\nabla f|Gradient →
“In which direction does the temperature decrease most rapidly?”
Opposite the gradient.−∇T-\nabla TGradient →
“She wishes to stay at the same temperature … Find a direction in which the initial rate of change of the temperature is 00”
Any direction perpendicular to the gradient.∇T⋅u=0\nabla T \cdot \mathbf u = 0Gradient →
“Find a unit vector uu that is tangent to the level curve of f(x,y)f(x, y)”
Tangent to a level curve means perpendicular to ∇f\nabla f: swap the components and change one sign.±⟨−fy, fx⟩∣∇f∣\pm\dfrac{\langle -f_y,\ f_x\rangle}{|\nabla f|}Gradient →
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