Does the function have a maximum or a minimum on the curve ? Explain.
Find all maxima and minima of on the curve .
Answer
(a) does not have a maximum. It does have a minimum.
(b) The minima are at , where takes the value .
Partial Derivatives
30 problems · hints, answers and solutions shown beside each one
Do you understand the idea? Usually little or no calculation.
Does the function have a maximum or a minimum on the curve ? Explain.
Find all maxima and minima of on the curve .
(a) does not have a maximum. It does have a minimum.
(b) The minima are at , where takes the value .
The surface is given by the equation . You are walking on measuring the function as you go. You are currently at the point where takes its largest value on , and are walking in the direction . Because you are walking on , the vector is tangent to at .
What is the directional derivative of at in the direction ? Do not use the method of Lagrange multipliers.
What is the directional derivative of at in the direction ? This time use the method of Lagrange multipliers.
(a) The function decreases, or at least does not increase, as you leave
in the direction .
The function also decreases, or at least does not increase, as you leave
in the direction .
(a), (b)
Practising the skill itself, until applying it is automatic.
The max is and the min is .
Find and so that the volume of an ellipsoid passing through the point is as small as possible.
The ellipsoid passes through the point if and only if .
.
Use the Method of Lagrange Multipliers to find the minimum value of subject to . At which point or points does the minimum occur?
The minimum value is at .
Use the Method of Lagrange Multipliers to find the radius of the base and the height of a right circular cylinder of maximum volume which can be fit inside the unit sphere .
and .
Use the method of Lagrange Multipliers to find the maximum and minimum values of
subject to the constraint
The maximum and minimum values of are and , respectively.
min, max.
Use Lagrange multipliers to find the points on the sphere closest to and farthest from the point .
is the closest point. is the farthest point.
Use Lagrange multipliers to find the maximum and minimum values of the function on the curve of intersection of the plane and the paraboloid .
The maximum is and the minimum is .
Find the point (with , and ) on the surface that is closest to the origin.
Find the maximum value of on the ellipsoid
Specify all points at which this maximum value occurs.
The maximum is and is achieved at and .
Find the radius of the largest sphere centred at the origin that can be inscribed inside (that is, enclosed inside) the ellipsoid
Let be the intersection of the plane and the sphere .
Use Lagrange multipliers to find the maximum value of on .
What are the coordinates of the lowest point on ?
(a) (b)
Use Lagrange multipliers to find the extreme values of
on the sphere .
Find the point on the sphere that is farthest from the point .
(a) The min is and the max is . (b)
Find the minimum of the function
subject to the constraint , using the method of Lagrange multipliers.
Give a geometric interpretation of this problem.
(a)
(b) The minimum of subject to the constraint is the square of the distance from to the point on the sphere that is nearest .
Use Lagrange multipliers to find the minimum and maximum values of subject to .
The maximum value is and the minimum value is .
Find the points on the ellipse which are closest to and farthest from the origin.
The farthest points are . The nearest points are .
The ends of the major axes are the points on the ellipse which are farthest from the origin. The ends of the minor axes are the points on the ellipse which are closest to the origin.
The ends of the minor axes are . The ends of the major axes are .
A closed rectangular box with a volume of 96 cubic meters is to be constructed of two materials. The material for the top costs twice as much per square meter as that for the sides and bottom. Use the method of Lagrange multipliers to find the dimensions of the least expensive box.
Consider the unit sphere
in . Assume that the temperature at a point of is
Find the hottest and coldest temperatures on .
The hottest temperature is and the coldest temperature is .
Find the dimensions of the box of maximum volume which has its faces parallel to the coordinate planes and which is contained inside the region .
A rectangular bin is to be made of a wooden base and heavy cardboard with no top. If wood is three times more expensive than cardboard, find the dimensions of the cheapest bin which has a volume of .
A closed rectangular box having a volume of cubic metres is to be built with material that costs $8 per square metre for the sides but $12 per square metre for the top and bottom. Find the least expensive dimensions for the box.
Suppose that , , are all greater than zero and let be the pyramid bounded by the plane and the 3 coordinate planes. Use the method of Lagrange multipliers to find the largest possible volume of if the plane is required to pass through the point . (The volume of a pyramid is equal to one-third of the area of its base times the height.)
, , , max volume
Further than practice: several ideas at once, or an unfamiliar situation.
Use Lagrange multipliers to find the minimum distance from the origin to all points on the intersection of the curves
Find the largest and smallest values of
on the sphere . Determine all points at which these values occur.
The min is at and the max is at .
The temperature in the plane is given by .
Give the system of equations that must be solved in order to find the warmest and coolest point on the circle by the method of Lagrange multipliers.
Find the warmest and coolest points on the circle by solving that system.
Give the system of equations that must be solved in order to find the critical points of .
Find the critical points by solving that system.
Find the coolest point on the solid disc .
(a) (i)
(a) (ii) The warmest point is and the coolest point is .
(b) (i)
(b) (ii) and
(c)
By finding the points of tangency, determine the values of for which is a tangent plane to the surface .
Use the method of Lagrange Multipliers to determine the absolute maximum and minimum values of the function along the surface .
Why do you get the same answers in (a) and (b)?
(a) (b)
(c) The level surfaces of are planes with equation of the form . To find the largest (smallest) value of on we keep increasing (decreasing) until we get to the largest (smallest) value of for which the plane intersects . For this value of , is tangent to .
Let have continuous partial derivatives. Consider the problem of finding local minima and maxima of on the curve .
Define . According to the method of Lagrange multipliers, if is a local minimum or maximum of on the curve , then there is a real number such that
On the curve , we have and . Define . If is a local minimum or maximum of , we have that
Show that (E1) is equivalent to (E2), in the sense that
See the solution.
From the UBC Math 200 open textbook project, © Joel Feldman, Andrew Rechnitzer, Elyse Yeager and others. Licensed CC BY-NC-SA 4.0; this HTML adaptation is released under the same licence. Full attribution.