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Sequences and Series

3.5 Power Series

27 problems · hints, answers and solutions shown beside each one

1Stage 1Conceptual

Do you understand the idea? Usually little or no calculation.

Q1Stage 1

Suppose f(x)=∑n=0∞(3−x4)nf(x)=\displaystyle\sum_{n=0}^\infty\left(\dfrac{3-x}{4}\right)^n. What is f(1)f(1)?

Hint

f(1)f(1) is the sum of a geometric series.

Answer

2

Full solution
Q2Stage 1

Suppose f(x)=∑n=1∞(x−5)nn!+2f(x)=\displaystyle\sum_{n=1}^\infty \dfrac{(x-5)^n}{n!+2}. Give a power series representation of f′(x)f'(x).

Hint

Calculate ddx{(x−5)nn!+2}\displaystyle\diff{}{x}\left\{\frac{(x-5)^n}{n!+2}\right\} when nn is a constant.

Answer

f(x)=∑n=1∞n(x−5)n−1n!+2f(x)=\displaystyle\sum_{n=1}^\infty \dfrac{n(x-5)^{n-1}}{n!+2}

Full solution
Q3Stage 1

Let f(x)=∑n=a∞An(x−c)nf(x)=\displaystyle \sum_{n=a}^\infty A_n(x-c)^n for some positive constants aa and cc, and some sequence of constants {An}\{A_n\}. For which values of xx does f(x)f(x) definitely converge?

Hint

There is only one.

Answer

only x=cx=c

Full solution
Q4Stage 1

Let f(x)f(x) be a power series centred at c=5c=5. If f(x)f(x) converges at x=−1x=-1, and diverges at x=11x=11, what is the radius of convergence of f(x)f(x)?

Hint

Use Theorem 3.5.9 in the CLP-2 text.

Answer

R=6R=6

Full solution

2Stage 2Procedural

Practising the skill itself, until applying it is automatic.

Q5Stage 2Past exam · M105 2012A

(a) Find the radius of convergence of the series

∑k=0∞(−1)k2k+1xk\begin{equation*} \sum_{k=0}^\infty (-1)^k 2^{k+1} x^k \end{equation*}

(b) You are given the formula for the sum of a geometric series, namely:

1+r+r2+⋯=11−r,∣r∣<1\begin{equation*} 1+r+r^2 + \cdots =\frac{1}{1-r},\qquad|r|<1 \end{equation*}

Use this fact to evaluate the series in part (a).

Hint

Review the discussion immediately following Definition 3.5.1 in the

CLP-2 text.

Answer

(a) R=12R = \dfrac{1}{2} (b) 21+2x\dfrac{2}{1+2x} for all ∣x∣<12|x|<\dfrac{1}{2}

Full solution
Q6Stage 2Past exam · M105 2014A

Find the radius of convergence for the power series ∑k=0∞xk10k+1(k+1)!\displaystyle\sum_{k=0}^\infty \frac{x^k}{10^{k+1}(k+1)!}

Hint

Review the discussion immediately following Definition 3.5.1 in the

CLP-2 text.

Answer

R=∞R = \infty

Full solution
Q7Stage 2Past exam · 2014A

Find the radius of convergence for the power series ∑n=0∞(x−2)nn2+1\displaystyle\sum_{n=0}^\infty \frac{(x - 2)^n}{n^2+1} .

Hint

Review the discussion immediately following Definition 3.5.1 in the

CLP-2 text.

Answer

11

Full solution
Q8Stage 2Past exam · 2013A

Consider the power series ∑n=1∞(−1)n(x+2)nn\displaystyle\sum\limits_{n=1}^\infty \frac{(-1)^n(x+2)^n}{\sqrt{n}}, where xx is a real number. Find the interval of convergence of this series.

Hint

See Example 3.5.11 in the

CLP-2 text.

Answer

The interval of convergence is −1<x+2≤1-1<x+2\le 1 or (−3,−1](-3,-1].

Full solution
Q9Stage 2Past exam · 2016Q5

Find the radius of convergence and interval of convergence of the series

∑n=0∞(−1)nn+1(x+13)n\begin{align*} \sum_{n=0}^{\infty} \frac{(-1)^n}{n+1} \left(\frac{x+1}{3}\right)^n \end{align*}
Hint

See Example 3.5.11 in the

CLP-2 text.

Answer

The radius of convergence is 33. The interval of convergence is −4<x≤2-4<x\le2, or simply (−4,2](-4,2].

Full solution
Q10Stage 2Past exam · 2015A

Find the interval of convergence for the power series

∑n=1∞(x−2)nn4/5(5n−4).\begin{align*} \sum_{n=1}^\infty \frac{(x-2)^n}{n^{4/5}(5^n-4)}. \end{align*}
Answer

−3≤x<7-3\le x< 7 or [−3,7)[-3,7)

Full solution
Q11Stage 2Past exam · 2016Q6

Find all values xx for which the series ∑n=1∞(x+2)nn2\displaystyle\sum_{n=1}^\infty\frac{(x+2)^n}{n^2} converges.

Answer

The given series converges if and only if −3≤x≤−1-3\le x\le -1. Equivalently, the series has interval of convergence [−3,−1][-3,-1].

Full solution
Q12Stage 2Past exam · 2016Q6

Find the interval of convergence for the following series.

  1. ∑n=1∞4nn(x−1)n\displaystyle \sum_{n=1}^\infty \frac{4^n}{n}(x-1)^n.

  2. ∑n=1∞4nn(2x+1)n\displaystyle \sum_{n=1}^\infty \frac{4^n}{n}(2x+1)^n.

  3. ∑n=1∞4nn(2x+1)2n\displaystyle \sum_{n=1}^\infty \frac{4^n}{n}(2x+1)^{2n}.

Answer

(a) 34≤x<54\frac{3}{4}\le x<\frac{5}{4} or [34,54)\big[\frac{3}{4},\frac{5}{4}\big) (b) −58≤x<−38-\frac{5}{8}\le x<-\frac{3}{8} or [−58,−38)\big[-\frac{5}{8},-\frac{3}{8}\big) (c) −34<x<−14-\frac{3}{4}< x<-\frac{1}{4}, or (−34,−14)\big(-\frac{3}{4},-\frac{1}{4}\big)

Full solution
Q13Stage 2Past exam · 2012A

Find, with explanation, the radius of convergence and the interval of convergence of the power series

∑n=0∞(−1)n(x−1)n2n(n+2)\begin{equation*} \sum_{n=0}^\infty (-1)^n\frac{(x-1)^n}{2^n(n+2)} \end{equation*}
Answer

The radius of convergence is 22. The interval of convergence is −1<x≤3-1< x\le3, or (−1,3]\big(-1,3\big].

Full solution
Q14Stage 2Past exam · 2014D

Find the interval of convergence for the series ∑n=1∞(−1)nn2(x−a)2n\displaystyle \sum_{n=1}^\infty (-1)^n n^2(x-a)^{2n} where aa is a constant.

Answer

The interval of convergence is a−1<x<a+1a-1< x<a+1, or (a−1,a+1)\big(a-1,a+1\big).

Full solution
Q15Stage 2Past exam · 2015A

Find the interval of convergence of the following series:

  1. ∑k=1∞(x+1)kk29k{\displaystyle \sum_{k=1}^\infty \frac{(x+1)^k}{k^2 9^k}}.

  2. ∑k=1∞ak(x−1)k{\displaystyle \sum_{k=1}^\infty a_k(x-1)^k}, where ak>0a_k>0 for k=1,2,⋯k=1,2,\cdots and ∑k=1∞(akak+1−ak+1ak+2)=a1a2{\displaystyle \sum_{k=1}^\infty \Big(\frac{a_k}{a_{k+1}} -\frac{a_{k+1}}{a_{k+2}}\Big) =\frac{a_1}{a_2} }.

Hint

Start part (b) by computing the partial sums of ∑k=1∞(akak+1−ak+1ak+2){\displaystyle \sum_{k=1}^\infty \Big(\frac{a_k}{a_{k+1}} -\frac{a_{k+1}}{a_{k+2}}\Big)}

Answer

(a) ∣x+1∣≤9|x+1|\le 9 or −10≤x≤8-10\le x\le 8 or [−10,8][-10,8] (b) This series converges only for x=1x=1.

Full solution
Q16Stage 2Past exam · 2014A

Find a power series representation for x31−x\dfrac{x^3}{1-x}.

Hint

You should know a power series representation for 11−x\dfrac{1}{1-x}. Use it.

Answer

∑n=0∞xn+3=∑n=3∞xn\displaystyle\sum\limits_{n=0}^\infty x^{n+3} =\sum\limits_{n=3}^\infty x^{n}

Full solution
Q17Stage 2

Suppose f′(x)=∑n=0∞(x−1)nn+2f'(x)=\displaystyle\sum_{n=0}^\infty \frac{(x-1)^{n}}{n+2}, and ∫5xf(t)dt=3x+∑n=1∞(x−1)n+1n(n+1)2\displaystyle \int_5^x f(t)\dee{t}=3x+\displaystyle\sum_{n=1}^\infty \frac{(x-1)^{n+1}}{n(n+1)^2}.

Give a power series representation of f(x)f(x).

Hint

You can safely ignore one of the given equations, but not the other.

Answer

f(x)=3+∑n=1∞(x−1)nn(n+1)f(x)=3+\displaystyle\sum_{n=1}^\infty \frac{(x-1)^{n}}{n(n+1)}

Full solution

3Stage 3Application

Further than practice: several ideas at once, or an unfamiliar situation.

Q18Stage 3Past exam · M121 2002A

Determine the values of xx for which the series

∑n=2∞xn32nlog⁡n\begin{equation*} \sum_{n=2}^\infty\frac{x^n}{3^{2n}\log n} \end{equation*}

converges absolutely, converges conditionally, or diverges.

Hint

n≥log⁡nn\ge\log n for all n≥1n\ge 1.

Answer

The series converges absolutely for ∣x∣<9|x|<9, converges conditionally for x=−9x=-9 and diverges otherwise.

Full solution
Q19Stage 3Past exam · 2013A

(a) Find the power–series representation for ∫11+x3 dx\displaystyle\int\frac{1}{1+x^3}\,\dee{x} centred at 00 (i.e. in powers of xx).

(b) The power series above is used to approximate ∫01/411+x3 dx\displaystyle\int_0^{1/4}\frac{1}{1+x^3}\,\dee{x}. How many terms are required to guarantee that the resulting approximation is within 10−510^{-5} of the exact value? Justify your answer.

Hint

See Example 3.5.21 in the

CLP-2 text. For part (b), review § 3.3.4 in the

CLP-2 text.

Answer

(a) ∑n=0∞(−1)nx3n+13n+1+C\displaystyle\sum\limits_{n=0}^\infty(-1)^n \frac{x^{3n+1}}{3n+1} +C (b) We need to keep two terms (the n=0n=0 and n=1n=1 terms).

Full solution
Q20Stage 3Past exam · 2014A

(a) Show that ∑n=0∞nxn=x(1−x)2\displaystyle\sum_{n=0}^\infty nx^n =\frac{x}{(1-x)^2} for −1<x<1-1<x<1.

(b) Express ∑n=0∞n2xn\displaystyle\sum_{n=0}^\infty n^2x^n as a ratio of polynomials. For which xx does this series converge?

Hint

You know the geometric series expansion of 11−x\frac{1}{1-x}. What (calculus) operation(s) can you apply to that geometric series to convert it into the given series?

Answer

(a) See the solution.

(b) ∑n=0∞n2xn=x(1+x)(1−x)3\displaystyle\sum\limits_{n=0}^\infty n^2 x^n=\frac{x(1+x)}{(1-x)^3}. The series converges for −1<x<1-1<x<1.

Full solution
Q21Stage 3Past exam · 2015A

Suppose that you have a sequence {bn}\{b_n\} such that the series ∑n=0∞(1−bn)\sum_{n=0}^{\infty}(1-b_n) converges. Using the tests we've learned in class, prove that the radius of convergence of the power series ∑n=0∞bnxn\displaystyle\sum_{n=0}^{\infty}b_nx^n is equal to 11.

Hint

First show that the fact that the series ∑n=0∞(1−bn)\sum_{n=0}^{\infty}(1-b_n) converges guarantees that lim⁡n→∞bn=1\lim_{n\rightarrow\infty}b_n=1.

Answer

See the solution.

Full solution
Q22Stage 3Past exam · M121 2014A

Assume {an}\big\{a_n \big\} is a sequence such that nanna_n decreases to CC as n→∞n \rightarrow\infty for some real number C>0C > 0

(a) Find the radius of convergence of ∑n=1∞anxn\displaystyle\sum\limits_{n=1}^\infty a_n x^n . Justify your answer carefully.

(b) Find the interval of convergence of the above power series, that is, find all xx for which the power series in (a) converges. Justify your answer carefully.

Hint

What does ana_n look like for large nn?

Answer

(a) 11. (b) The series converges for −1≤x<1-1\le x<1, i.e. for the interval [−1,1)[-1,1)

Full solution
Q23Stage 3

An infinitely long, straight rod of negligible mass has the following weights:

  • At every whole number nn, a mass of weight 12n\dfrac{1}{2^n} at position nn, and

  • a mass of weight 13n\dfrac{1}{3^n} at position −n-n.

At what position is the centre of mass of the rod?

Figure from prob_s3.5, line 2

Figure from prob_s3.5, line 2

Hint

Equation 2.3.1 in the CLP-2 text tells us the centre of mass of a rod with weights {mn}\{m_n\} at positions {xn}\{x_n\} is xˉ=∑mnxn∑mn\displaystyle\bar x =\frac{\sum m_nx_n}{\sum m_n} .

Answer

56\dfrac{5}{6}

Full solution
Q24Stage 3

Let f(x)=∑n=0∞An(x−c)nf(x)=\displaystyle\sum_{n=0}^{\infty}A_n(x-c)^n, for some constant cc and a sequence of constants {An}\{A_n\}. Further, let f(x)f(x) have a positive radius of convergence.

If A1=0A_1=0, show that y=f(x)y=f(x) has a critical point at x=cx=c. What is the relationship between the behaviour of the graph at that point and the value of A2A_2?

Hint

Use the second derivative test.

Answer

The point x=cx=c corresponds to a local maximum if A2<0A_2<0 and a local minimum if A2>0A_2>0.

Full solution
Q25Stage 3

Evaluate ∑n=3∞n5n−1\displaystyle \sum_{n=3}^\infty \frac{n}{5^{n-1}}.

Hint

What function has ∑n=1∞nxn−1\displaystyle\sum_{n=1}^\infty nx^{n-1} as its power series representation?

Answer

1380\dfrac{13}{80}

Full solution
Q26Stage 3

Find a polynomial that approximates f(x)=log⁡(1+x)f(x)=\log(1+ x) to within an error of 10−510^{-5} for all values of xx in (0,110)\left(0,\frac{1}{10}\right).

Then, use your polynomial to approximate log⁡(1.05)\log(1.05) as a rational number.

Hint

The power series representation in Example 3.5.20 is an alternating series when xx is positive.

Answer

x−x22+x33−x44x-\dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}

Full solution
Q27Stage 3

Find a polynomial that approximates f(x)=arctan⁡xf(x)=\arctan x to within an error of 10−510^{-5} for all values of xx in (−14,14)\left(-\frac{1}{4},\frac{1}{4}\right).

Hint

The power series representation in Example 3.5.21 is an alternating series when xx is nonzero.

Answer

x−x33+x55x-\dfrac{x^3}{3}+\dfrac{x^5}{5}

Full solution

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From the UBC Math 101 open textbook project, © Joel Feldman, Andrew Rechnitzer, Elyse Yeager and others. Licensed CC BY-NC-SA 4.0; this HTML adaptation is released under the same licence. Full attribution.