Select the series below that diverge by the divergence test.
(A) (B) (C) (D)
Sequences and Series
53 problems · hints, answers and solutions shown beside each one
Do you understand the idea? Usually little or no calculation.
That is, which series have terms whose limit is not zero?
(B), (C)
Select the series below whose terms satisfy the conditions to apply the integral test.
(A) (B) (C) (D)
That is, if is a function with for all whole numbers , is nonnegative and decreasing?
(A)
Suppose there is some threshold after which a person is considered old, and before which they are young.
Let Olaf be an old person, and let Yuan be a young person.
Suppose I am older than Olaf. Am I old?
Suppose I am younger than Olaf. Am I old?
Suppose I am older than Yuan. Am I young?
Suppose I am younger than Yuan. Am I young?
This isn't a trick. It's meant to give you intuition to the direct comparison test.
(a) I am old (b) not enough information to tell
(c) not enough information to tell (d) I am young
Below are graphs of two sequences with positive terms. Assume the sequences continue as shown. Fill in the table with conclusions that can be made from the direct comparison test, if any.
| if converges | if diverges | |
| [10pt] and if is the red series | then \rule1.5cm1pt | then \rule1.5cm1pt |
| [10pt] and if is the blue series | then \rule1.5cm1pt | then \rule1.5cm1pt |
| [10pt] |
The comparison test is Theorem 3.3.8 in the CLP-2 text. However, rather than trying to memorize which way the inequalities go in all cases, you can use the same reasoning as Question 3.
| if converges | if diverges | |
| [10pt] and if is the red series | then CONVERGES | inconclusive |
| [10pt] and if is the blue series | inconclusive | then DIVERGES |
| [10pt] |
For each pair of series below, decide whether the second series is a valid comparison series to determine the convergence of the first series, using the direct comparison test and/or the limit comparison test.
compared to the divergent series
compared to the convergent series
compared to the convergent series
compared to the divergent series
Think about Question 4 to remind yourself which way the inequalities have to go for direct comparison.
Note that all the comparison series have positive terms, so we don't need to worry about that part of the limit comparison test.
(a) both direct comparison and limit comparison (b) direct comparison
(c) limit comparison (d) neither
Suppose is a sequence with . Does converge or diverge, or is it not possible to determine this from the information given? Why?
The divergence test is Theorem 3.3.1 in the CLP-2 text.
It diverges by the divergence test, because .
What flaw renders the following reasoning invalid?
Q: Determine whether converges or diverges.
A: First, we will evaluate .
Note for .
Note also that .
Therefore, by the Squeeze Theorem, as well.
So, by the divergence test, converges.
The limit is calculated correctly.
We cannot use the divergence test to show that a series converges. It is inconclusive in this case.
What flaw renders the following reasoning invalid?
Q: Determine whether converges or diverges.
A: We use the integral test. Let . Note is always positive, since . Also, is continuous.
By the integral test, since the integral diverges, also diverges.
It is true that is positive. What else has to be true of for the integral test to apply?
The integral test does not apply because is not decreasing.
What flaw renders the following reasoning invalid?
Q: Determine whether the series
converges or diverges.
A: We want to compare this series to the series . Note both this series and the series in the question have positive terms.
First, we find that when is sufficiently large. The justification for this claim is as follows:
We note that for sufficiently large.
Therefore,
Therefore,
Since and are both expressions that work out to be positive for the values of under consideration, we can divide both sides of the inequality by these terms without having to flip the inequality. So, .
Now, we claim converges.
Note . This is a geometric series with . Since , the series converges.
Now, by the Direct Comparison Test, we conclude that converges.
Refer to Question 4.
The inequality goes the wrong way, so the direct comparison test (with this comparison series) is inconclusive.
The definition of an alternating series is given in the start of Section 3.3.4 in the CLP-2 text.
(B), (D)
For the ratio test to be inconclusive, should be 1 or nonexistent.
One possible answer: .
Imagine you're taking an exam, and you momentarily forget exactly how the inequality in the ratio test works. You remember there's a ratio, but you don't remember which term goes on top; you remember there's something about the limit being greater than or less than one, but you don't remember which way implies convergence.
Explain why
or, equivalently,
should mean that the sum diverges (rather than converging).
By the divergence test, for a series to converge, we need . That is, the magnitude (absolute value) of the terms needs to be getting smaller.
By the divergence test, for a series to converge, we need . That is, the magnitude (absolute value) of the terms needs to be getting smaller. If or (equivalently) , then for sufficiently large , so the terms are actually growing in magnitude. That means the series diverges, by the divergence test.
Give an example of a series , with a function such that for all whole numbers , such that:
diverges, while
converges.
If is positive and decreasing, then the integral test tells you that the integral and the series either both increase or both decrease. So, in order to find an example with the properties required in the question, you need to not be both positive and decreasing.
One possible answer: , for every .
By the integral test, any answer will use a function that is not both positive and decreasing.
Suppose that you want to use the Limit Comparison Test on the series where . Write down a sequence such that exists and is nonzero. (You don't have to carry out the Limit Comparison Test)
Review Theorem 3.3.11 and Example 3.3.12 in the CLP-2 text.
One possible answer:
Decide whether each of the following statements is true or false. If false, provide a counterexample. If true provide a brief justification.
If , then converges.
If , then converges.
If and diverges, then diverges.
Don't jump to conclusions about properties of the 's.
(a) In general false. The harmonic series provides a counterexample.
(b) In general false. If , then is again the harmonic series , which diverges.
(c) In general false. Take, for example, and .
Practising the skill itself, until applying it is automatic.
Always try the divergence test first (in your head).
No. It diverges.
Which test should you always try first (in your head)?
It diverges.
Determine whether the series is convergent or divergent. If it is convergent, find its value.
Review the integral test, which is Theorem 3.3.5 in the CLP-2 text.
The series diverges.
A comparison might be helpful–try some algebraic manipulation to find a likely series to compare it to.
It diverges.
This is a geometric series.
This is a geometric series with . Since , it is divergent.
Notice that the series is geometric, but it doesn't start at .
The series converges to .
Note only takes integer values: what's when is an integer?
The series converges.
Note only takes integer values: what's when is an integer?
It diverges.
What's the test that you should always think of when you see a factorial?
The series converges.
This is a geometric series, but you'll need to do a little algebra to figure out .
The series converges to .
Which test fits most often with factorials?
The series converges.
Try finding a nice comparison.
It converges.
With the substitution , the function is easily integrable.
Let . Then is positive and decreases as increases. So the sum and the integral either both converge or both diverge, by the integral test, which is Theorem 3.3.5 in the CLP-2 text. For the integral, we use the substitution , to get
which converges by the –test (which is Example 1.12.8 in the CLP-2 text) with .
Combine the integral test with the results about -series, Example 3.3.6 in the CLP-2 text.
Try the substitution .
It converges.
Use the comparison test (not the limit comparison test) to show whether the series
converges or diverges.
Review Example 3.3.9 in the CLP-2 text for developing intuition about comparisons, and Example 3.3.10 for an example where finding an appropriate comparison series calls for some creativity.
The series converges by the –test with .
Note that
for all . As the series converges, the comparison test says that converges too.
What does the summand look like when is very large?
The series converges.
What does the summand look like when is very large?
It diverges.
Determine, with explanation, whether each of the following series converge or diverge.
is a sneaky way to write .
(a) diverges (b) converges
What is the behaviour for large ?
The series diverges.
When is large, .
(a) converges (b) diverges
This is a geometric series, but it doesn't start at .
Determine whether the series is convergent or divergent. If it is convergent, find its value.
The series is geometric.
Determine, with explanation, whether each of the following series converge or diverge.
.
The first series can be written as .
(a) diverges by limit comparison with the harmonic series
(b) converges by the ratio test
Determine, with explanation, whether each of the following series converges or diverges.
.
.
.
(a) Converges by the limit comparison test with .
(b) Diverges by the ratio test.
(c) Diverges by the integral test.
What does the summand look like when is very large?
It converges.
What is the smallest value of such that the partial sum approximates within an accuracy of ?
Review the alternating series test, which is given in Theorem 3.3.14 in the CLP-2 text.
It is known that (you don't have to show this). Find so that , the partial sum of the series, satisfies . Be sure to say why your method can be applied to this particular series.
Review the alternating series test, which is given in Theorem 3.3.14 in the CLP-2 text.
The series converges to some number (you don't have to prove this). According to the Alternating Series Estimation Theorem, what is the smallest value of for which the partial sum of the series is at most away from ? For this value of , write out the partial sum of the series.
Review the alternating series test, which is given in Theorem 3.3.14 in the
CLP-2 text.
We need and then
Further than practice: several ideas at once, or an unfamiliar situation.
Determine, with explanation, whether the following series converge or diverge.
(a) converges (b) converges
(a) Prove that diverges.
(b) Explain why you cannot conclude that diverges from part (a) and the Integral Test.
(c) Determine, with explanation, whether converges or diverges.
For part (a), see Example 1.12.23 in the
CLP-2 text.
For part (b), review Theorem 3.3.5 in the
CLP-2 text.
For part (c), see Example 3.3.12 in the
CLP-2 text.
(a) See the solution.
(b) is not a decreasing function.
(c) See the solution.
Show that converges and find an interval of length or less that contains its exact value.
The truncation error arising from the approximation is precisely . You'll want to find a bound on this sum using the integral test.
A key observation is that, since is decreasing, we can show that
for every .
The sum is between 0.9035 and 0.9535.
Suppose that the series converges and that for all . Prove that the series also converges.
What does the fact that the series converges guarantee about the behavior of for large ?
Since , there must be some integer such that for all . Then, for ,
From the information in the problem statement, we know
So, by the direct comparison test,
Since the convergence of a series is not affected by its first terms, as long as is finite, we conclude
Suppose that the series converges, where for . Determine whether the series converges or diverges.
What does the fact that the series converges guarantee about the behavior of for large ?
It diverges.
Assume that the series converges, where for . Is the following series
convergent? If your answer is NO, justify your answer. If your answer is YES, evaluate the sum of the series .
What does the fact that the series converges guarantee about the behavior of for large ?
It converges to ,
Prove that if for all and if the series converges, then the series also converges.
What does the fact that the series converges guarantee about the behavior of for large ? When is ?
See the solution.
Suppose the frequency of word use in a language has the following pattern:
The -th most frequently used word accounts for percent of the total words used.
So, in a text of 100 words, we expect the most frequently used word to appear times, while the second-most-frequently used word should appear about times, and so on.
If books written in this language use distinct words, then the most commonly used word accounts for roughly what percentage of total words used?
If we add together the frequencies of all the words, they should amount to 100%. We can approximate this sum using ideas from Example 3.3.4 in the CLP-2 text.
About 9% to 10%
Suppose the sizes of cities in a country adhere to the following pattern: if the largest city has population , then the -th largest city has population .
If the largest city in this country has 2 million people and the smallest city has 1 person, then the population of the entire country is . (For many 's in this sum is not an integer. Ignore that.) Evaluate this sum approximately, with an error of no more than 1 million people.
We are approximating a finite sum — not an infinite series. To get greater accuracy, use exact values for the first several terms in the sum, and use an integral to approximate the rest.
The total population is between 29,820,091 and 30,631,021 people.
From the UBC Math 101 open textbook project, © Joel Feldman, Andrew Rechnitzer, Elyse Yeager and others. Licensed CC BY-NC-SA 4.0; this HTML adaptation is released under the same licence. Full attribution.