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Sequences and Series

3.2 Series

33 problems · hints, answers and solutions shown beside each one

1Stage 1Conceptual

Do you understand the idea? Usually little or no calculation.

Q1Stage 1

Write out the first five partial sums corresponding to the series ∑n=1∞1n\displaystyle\sum_{n=1}^{\infty} \frac{1}{n}.

You don't need to simplify the terms.

Hint

SNS_N is the sum of the terms corresponding to n=1n=1 through n=Nn=N.

Answer

NSN1121+1231+12+1341+12+13+1451+12+13+14+15\begin{array}{l|l} \mathbf{N}&\mathbf{S_N}\\ \hline 1 & 1\\[7pt] 2 & 1+\frac12\\[7pt] 3 & 1+\frac12 + \frac13\\[7pt] 4 & 1+\frac12 + \frac13+\frac14\\[7pt] 5 & 1+\frac12 + \frac13+\frac14+\frac15\\[7pt] \end{array}

Full solution
Q2Stage 1

Every student who comes to class brings their instructor cookies, and leaves them on the instructor's desk. Let CkC_k be the total number of cookies on the instructor's desk after the kkth student comes.

If C11=20C_{11}=20, and C10=17C_{10}=17, how many cookies did the 11th student bring to class?

Hint

Note CkC_k is the cumulative number of cookies.

Answer

3

Full solution
Q3Stage 1

Suppose the sequence of partial sums of the series ∑n=1∞an\displaystyle\sum_{n=1}^\infty a_n is {SN}={NN+1}\{S_N\} = \left\{\dfrac{N}{N+1}\right\}.

  1. What is {an}\{a_n\}?

  2. What is lim⁡n→∞an\lim\limits_{n \to \infty} a_n?

  3. Evaluate ∑n=1∞an\displaystyle\sum_{n=1}^\infty a_n.

Hint

How is (a) related to Question 2?

Answer

(a) an={12 if n=11n(n+1) else \displaystyle a_n = \begin{cases} \frac12 &\text{ if } n=1\\ \dfrac{1}{n(n+1)} &\text{ else }\\ \end{cases} (b) 0 (c) 1

Full solution
Q4Stage 1

Suppose the sequence of partial sums of the series ∑n=1∞an\displaystyle\sum_{n=1}^\infty a_n is {SN}={(−1)N+1N}\{S_N\} = \left\{(-1)^N+\dfrac{1}{N}\right\}.

What is {an}\{a_n\}?

Hint

You'll have to calculate a1a_1 separately from the other terms.

Answer

an={0 if n=12(−1)n−1n(n−1) elsea_n=\begin{cases} 0 & \text{ if } n=1\\ 2(-1)^{n} -\frac{1}{n(n-1)} &\text{ else} \end{cases}

Full solution
Q5Stage 1

Let f(N)f(N) be a formula for the NNth partial sum of ∑n=1∞an\displaystyle\sum_{n=1}^\infty a_n. (That is, f(N)=SNf(N)=S_N.) If f′(N)<0f'(N)<0 for all N>1N > 1, what does that say about ana_n?

Hint

When does adding a number decrease the total sum?

Answer

an<0a_n < 0 for all n≥2n \geq 2

Full solution

Questions 6 through 8 invite you to explore geometric sums in a geometric way. This is complementary to than the algebraic method discussed in the text.

Q6Stage 1

Suppose the triangle outlined in red in the picture below has area one.

Figure from prob_s3.2, line 1

Figure from prob_s3.2, line 1

  1. Express the combined area of the black triangles as a series, assuming the pattern continues forever.

  2. Evaluate the series using the picture (not the formula from your book).

Hint

For (b), imagine cutting up the triangle into its black and white parts, then sharing it equally among a certain number of friends. What is the easiest number of friends to share with, making sure each has the same area in their pile?

Answer

(a) ∑n=1∞24n\displaystyle\sum_{n=1}^\infty \frac{2}{4^n} (b) 23\dfrac23

Full solution
Q7Stage 1

Suppose the square outlined in red in the picture below has area one.

Figure from prob_s3.2, line 1

Figure from prob_s3.2, line 1

  1. Express the combined area of the black squares as a series, assuming the pattern continues forever.

  2. Evaluate the series using the picture (not the formula from your book).

Hint

Compare to Question 6.

Answer

(a) ∑n=1∞19n\displaystyle\sum_{n=1}^\infty \frac{1}{9^n} (b) 18\dfrac{1}{8}

Full solution
Q8Stage 1

In the style of Questions 6 and 7, draw a picture that represents ∑n=1∞13n\displaystyle\sum_{n=1}^{\infty}\frac{1}{3^n} as an area.

Hint

Iteratively divide a shape into thirds.

Answer

Two possible pictures:

Figure from prob_s3.2, line 2

Figure from prob_s3.2, line 2

Figure from prob_s3.2, line 16

Figure from prob_s3.2, line 16

Full solution
Q9Stage 1

Evaluate ∑n=010015n\displaystyle\sum_{n=0}^{100}\frac{1}{5^n}.

Hint

Equation 3.2.1 in the CLP-2 text tells us ∑n=0Narn=a1−rN+11−r\displaystyle\sum_{n=0}^N ar^n = a\dfrac{1-r^{N+1}}{1-r}, for r≠1r \neq 1.

Answer

5101−14⋅5100\dfrac{5^{101}-1}{4\cdot 5^{100}}

Full solution
Q10Stage 1

Every student who comes to class brings their instructor cookies, and leaves them on the instructor's desk. Let CkC_k be the total number of cookies on the instructor's desk after the kkth student comes.

If C20=53C_{20}=53, and C10=17C_{10}=17, what does C20−C10=36C_{20}-C_{10}=36 represent?

Hint

Note CkC_k is the cumulative number of cookies.

Answer

All together, there were 36 cookies brought by Student 11 through Student 20.

Full solution
Q11Stage 1

Evaluate ∑n=5010015n\displaystyle\sum_{n=50}^{100}\frac{1}{5^n}. (Note the starting index.)

Hint

To adjust the starting index, either factor out the first term in the series, or subtract two series. For the subtraction option, consider Question 10.

Answer

551−14⋅5100\dfrac{5^{51}-1}{4\cdot 5^{100}}

Full solution
Q12Stage 1
  1. Starting on day d=1d=1, every day you give your friend $1d+1\frac{1}{d+1}, and they give $1d\frac{1}{d} back to you. After a long time, how much money have you gained by this arrangement?

  2. Evaluate ∑d=1∞(1d−1(d+1))\displaystyle\sum_{d=1}^\infty \left(\frac{1}{d}-\frac{1}{(d+1)}\right).

  3. Starting on day d=1d=1, every day your friend gives you $(d+1)(d+1), and they take $(d+2)(d+2) from you. After a long time, how much money have you gained by this arrangement?

  4. Evaluate ∑d=1∞((d+1)−(d+2))\displaystyle\sum_{d=1}^\infty \left((d+1)-(d+2)\right).

Hint

Express your gains in (a) and (c) as series.

Answer

(a) As time passes, your gains increase, approaching $1. (b) 1
(c) As time passes, you lose more and more money, without bound. (d) −∞-\infty

Full solution
Q13Stage 1

Suppose ∑n=1∞an=A\displaystyle\sum_{n=1}^\infty a_n = A, ∑n=1∞bn=B\displaystyle\sum_{n=1}^\infty b_n = B, and ∑n=1∞cn=C\displaystyle\sum_{n=1}^\infty c_n = C.

Evaluate ∑n=1∞(an+bn+cn+1)\displaystyle\sum_{n=1}^\infty\left( a_n+b_n+c_{n+1}\right).

Hint

To find the difference between ∑n=1∞cn\displaystyle\sum_{n=1}^\infty c_n and ∑n=1∞cn+1\displaystyle\sum_{n=1}^\infty c_{n+1}, try writing out the first few terms.

Answer

A+B+C−c1A+B+C-c_1

Full solution
Q14Stage 1

Suppose ∑n=1∞an=A\displaystyle\sum_{n=1}^\infty a_n = A, ∑n=1∞bn=B≠0\displaystyle\sum_{n=1}^\infty b_n = B \neq 0, and ∑n=1∞cn=C\displaystyle\sum_{n=1}^\infty c_n = C.

True or false: ∑n=1∞(anbn+cn)=AB+C\displaystyle\sum_{n=1}^\infty\left(\dfrac{ a_n}{b_n}+c_{n}\right) = \frac{A}{B}+C.

Hint

You might want to first consider a simpler true or false: ∑n=1∞anbn=?AB\displaystyle\sum_{n=1}^\infty \dfrac{ a_n}{b_n} \stackrel{?}{=} \dfrac{A}{B}.

Answer

in general, false

Full solution

2Stage 2Procedural

Practising the skill itself, until applying it is automatic.

Q15Stage 2Past exam · 2016Q5

To what value does the series 1+13+19+127+181+1243+⋯\displaystyle 1 + \frac{1}{3} + \frac{1}{9} + \frac{1}{27}+ \frac{1}{81}+ \frac{1}{243} + \cdots converge?

Hint

What kind of a series is this?

Answer

32\dfrac{3}{2}

Full solution
Q16Stage 2Past exam · M105 2015A

Evaluate ∑k=7∞18k\displaystyle \sum_{k=7}^{\infty} \frac{1}{8^k}

Hint

This is a special kind of series, that you should recognize.

Answer

17×86\dfrac{1}{7\times 8^6}

Full solution
Q17Stage 2Past exam · 2016Q5

Show that the series ∑k=1∞(6k2−6(k+1)2)\displaystyle \sum_{k=1}^{\infty} \bigg( \frac{6}{k^2} - \frac{6}{(k+1)^2} \bigg) converges and find its limit.

Hint

When you see ∑k(⋯k⋯  −  ⋯k+1⋯)\displaystyle\sum_k \Big(\cdots \textcolor{red}{k}\cdots \ \ -\ \ \cdots \textcolor{red}{k+1}\cdots\Big), you should think “telescoping series."

Answer

66

Full solution
Q18Stage 2Past exam · 2016A

Find the sum of the convergent series ∑n=3∞( ⁣cos⁡(πn)−cos⁡(πn+1))\displaystyle\sum\limits_{n=3}^\infty \bigg( \!\cos\Big( \frac \pi n \Big) - \cos\Big( \frac \pi{n+1} \Big) \bigg).

Hint

When you see ∑n(⋯n⋯  −  ⋯n+1⋯)\displaystyle\sum_n \Big(\cdots \textcolor{red}{n}\cdots \ \ -\ \ \cdots \textcolor{red}{n+1}\cdots\Big), you should immediately think “telescoping series”. But be careful not to jump to conclusions — evaluate the nthn^{\rm th} partial sum explicitly.

Answer

cos⁡(π3)−cos⁡(0)=−12\displaystyle\cos\left( \frac \pi 3 \right) - \cos(0) = -\frac{1}{2}

Full solution
Q19Stage 2Past exam · 2016Q5

The nthn^{\rm th} partial sum of a series ∑n=1∞an\displaystyle \sum_{n=1}^{\infty}a_n is known to have the formula sn=1+3n5+4n\displaystyle s_n = \frac{1+3n}{5+4n}.

  1. Find an expression for ana_n, valid for n≥2n\ge2.

  2. Show that the series ∑n=1∞an\displaystyle \sum_{n=1}^{\infty}a_n converges and find its value.

Hint

Review Definition 3.2.3 in the CLP-2 text.

Answer

(a) an=1116n2+24n+5\displaystyle a_n= \frac{11}{16n^2 + 24n +5} (b) 34\dfrac{3}{4}

Full solution
Q20Stage 2Past exam · 2013A

Find the sum of the series ∑n=2∞3⋅4n+18⋅5n\displaystyle\sum\limits_{n=2}^\infty \frac{3\cdot 4^{n+1}}{8\cdot 5^n}. Simplify your answer completely.

Hint

This is a special case of a general series whose sum we know.

Answer

245\dfrac{24}{5}

Full solution
Q21Stage 2Past exam · 2016Q5

Relate the number 0.23ˉ=0.233333…0.2\bar{3} = 0.233333\ldots to the sum of a geometric series, and use that to represent it as a rational number (a fraction or combination of fractions, with no decimals).

Hint

Review Example 3.2.5 in the CLP-2 text. To write the number as a geometric series, the first few terms might not fit the pattern of the rest of the terms.

Answer

730\dfrac{7}{30}

Full solution
Q22Stage 2Past exam · 2012A

Express 2.656565…2.656565\ldots as a rational number, i.e. in the form p/qp/q where pp and qq are integers.

Hint

Start by writing it as a geometric series.

Answer

26399\dfrac{263}{99}

Full solution
Q23Stage 2Past exam · 2016A

Express the decimal 0.321‾=0.321321321…0.\overline{321}=0.321321321\ldots as a fraction.

Hint

Review Example 3.2.5 in the CLP-2 text. Since the pattern repeats every three decimals, your common ratio rr will be 1103\dfrac{1}{10^3}.

Answer

321999=107333\dfrac{321}{999}= \dfrac{107}{333}

Full solution
Q24Stage 2Past exam · 2015A

Find the value of the convergent series

∑n=2∞(2n+13n+12n−1−12n+1)\begin{align*} \sum_{n=2}^\infty \bigg( \frac{2^{n+1}}{3^n} + \frac1{2n-1} - \frac1{2n+1} \bigg) \end{align*}

Simplify your answer completely.

Hint

Split the series into two parts.

Answer

33

Full solution
Q25Stage 2Past exam · M105 2014A

Evaluate

∑n=1∞[(13)n+(−25)n−1]\begin{align*} \sum_{n=1}^\infty\bigg[{\Big(\frac{1}{3}\Big)}^n + {\Big(-\frac{2}{5}\Big)}^{n-1}\bigg] \end{align*}
Hint

Split the series into two parts.

Answer

12+57=1714\dfrac{1}{2}+\dfrac{5}{7} =\dfrac{17}{14}

Full solution
Q26Stage 2Past exam · 2014D

Find the sum of the series ∑n=0∞1+3n+14n\displaystyle\sum_{n=0}^\infty\frac{1+3^{n+1}}{4^n}.

Hint

Split the series into two parts.

Answer

403\dfrac{40}{3}

Full solution
Q27Stage 2

Evaluate ∑n=5∞log⁡(n−3n)\displaystyle\sum_{n=5}^\infty \log\left(\frac{n-3}{n}\right).

Hint

Use logarithm rules to turn this into a more obvious telescoping series.

Answer

The series diverges to −∞-\infty.

Full solution
Q28Stage 2

Evaluate ∑n=2∞(2n−1n+1−1n−1)\displaystyle\sum_{n=2}^\infty \left(\frac{2}{n}-\frac{1}{n+1}-\frac{1}{n-1} \right).

Hint

This is a telescoping series.

Answer

−12-\dfrac12

Full solution

3Stage 3Application

Further than practice: several ideas at once, or an unfamiliar situation.

Q29Stage 3

An infinitely long, flat cliff has stones hanging off it, attached to thin wire of negligible mass. Starting at position x=1x=1, every metre (at position xx, where xx is some whole number) the stone has mass 14x\dfrac{1}{4^x} kg and is hanging 2x2^x metres below the top of the cliff.

Figure from prob_s3.2, line 1

Figure from prob_s3.2, line 1

Hint

The stone at position xx has mass 14x\dfrac{1}{4^x} kg, and we have to pull it a distance of 2x2^x metres. From this, you can find the work involved in pulling up a single stone. Then, add up the work involved in pulling up all the stones.

Answer

9.8 J

Full solution
Q30Stage 3

Find the combined volume of an infinite collection of spheres, where for each whole number n=1, 2, 3, …n=1,\,2,\,3,\,\ldots there is exactly one sphere of radius 1πn\dfrac{1}{\pi^n}.

Hint

The volume of a sphere of radius rr is 43πr3\dfrac{4}{3}\pi r^3.

Answer

4π3(π3−1)\dfrac{4\pi}{3\left(\pi^3-1\right)}

Full solution
Q31Stage 3

Evaluate ∑n=3∞(sin⁡2n2n+cos⁡2(n+1)2n+1)\displaystyle\sum_{n=3}^\infty \left(\frac{\sin^2 n}{2^n}+\frac{\cos^2(n+1)}{2^{n+1}} \right).

Hint

Use the properties of a telescoping series to simplify the terms.
Recall sin⁡2θ+cos⁡2θ=1\sin^2\theta+\cos^2\theta=1.

Answer

sin⁡238+32≈32.0025\displaystyle \frac{\sin^23}{8}+32\approx 32.0025

Full solution
Q32Stage 3

Suppose a series ∑n=1∞an\displaystyle\sum_{n=1}^\infty a_n has sequence of partial sums {SN}\{S_N\}, and the series ∑N=1∞SN\displaystyle\sum_{N=1}^\infty S_N has sequence of partial sums {SM}={∑N=1MSN}\{\mathscr S_M \}=\left\{ \displaystyle\sum_{N=1}^M S_N\right\}.

If SM=M+1M\mathscr S_M = \dfrac{M+1}{M}, what is ana_n?

Hint

Review Question 3 for using the sequence of partial sums.

Answer

an={2n(n−1)(n−2) if n≥3,−52 if n=2,2 if n=1\displaystyle a_n =\begin{cases} \frac{2}{n(n-1)(n-2)} &\text{ if }n \ge 3,\\ -\frac52 &\text{ if }n=2,\\ 2 &\text{ if }n=1 \end{cases}

Full solution
Q33Stage 3

Create a bullseye using the following method:

Starting with a red circle of area 1, divide the radius into thirds, creating two rings and a circle. Colour the middle ring blue.

Continue the pattern with the inside circle: divide its radius into thirds, and colour the middle ring blue.

Figure from prob_s3.2, line 2

Figure from prob_s3.2, line 2

Figure from prob_s3.2, line 10

Figure from prob_s3.2, line 10

Continue in this way indefinitely: dividing the radius of the innermost circle into thirds, creating two rings and another circle, and colouring the middle ring blue.

Figure from prob_s3.2, line 2

Figure from prob_s3.2, line 2

What is the area of the red portion?

Hint

What is the ratio of areas between the outermost (red) ring and the next (blue) ring?

Answer

58\dfrac{5}{8}

Full solution

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From the UBC Math 101 open textbook project, © Joel Feldman, Andrew Rechnitzer, Elyse Yeager and others. Licensed CC BY-NC-SA 4.0; this HTML adaptation is released under the same licence. Full attribution.