For which values of is the integral improper?
Hint
There are two kinds of impropreity in an integral: an infinite discontinuity in the integrand, and an infinite limit of integration.
Answer
Any real number in or , and .
Integration
27 problems · hints, answers and solutions shown beside each one
Do you understand the idea? Usually little or no calculation.
There are two kinds of impropreity in an integral: an infinite discontinuity in the integrand, and an infinite limit of integration.
Any real number in or , and .
The integrand is continuous for all .
Below are the graphs and . Suppose converges, and diverges. Assuming the graphs continue on as shown as , which graph is , and which is ?
What matters is which function is bigger for large values of , not near the origin.
The red function is , and the blue function is .
Decide whether the following statement is true or false. If false, provide a counterexample. If true, provide a brief justification. (Assume that and are continuous functions.)
If converges and for all , then converges.
Read both the question and Theorem 1.12.17 in the
CLP-2 text very carefully.
False. For example, the functions and provide a counterexample.
Let and . Note converges while diverges.
For each of the functions described below, decide whether converges or diverges, or whether there isn't enough information to decide. Justify your decision.
, continuous and defined for all , .
, continuous and defined for all , .
, continuous and defined for all , .
(a) What if is negative? What if it's not?
(b) What if is very close to or , rather than right in the middle?
(c) Note .
Not enough information to decide. For example, consider versus .
Not enough information to decide. For example, consider versus .
converges by the comparison test, since and converges.
Practising the skill itself, until applying it is automatic.
First: is the integrand unbounded, and if so, where?
Second: when evaluating integrals, always check to see if you can use a simple substitution before trying a complicated procedure like partial fractions.
The integral diverges.
Determine whether the integral is convergent or divergent. If it is convergent, find its value.
Is the integrand bounded?
The integral diverges.
See Example 1.12.21 in the
CLP-2 text. Rather than antidifferentiating, you can find a nice comparison.
The integral does not converge.
Which of the two terms in the denominator is more important when ? Which one is more important when is very large?
The integral converges.
Remember to break the integral into two pieces.
The integral diverges.
Remember to break the integral into two pieces.
The integral diverges.
The easiest test in this case is limiting comparison, Theorem 1.12.22 in the CLP-2 text.
The integral diverges.
Not all discontinuities cause an integral to be improper–only infinite discontinuities.
The integral diverges.
Determine (with justification!) which of the following applies to the integral :
diverges
converges but diverges
converges, as does
Remark: these options, respectively, are that the integral diverges, converges conditionally, and converges absolutely. You'll see this terminology used for series in Section 3.4.1 of the CLP-2 text.
Which of the two terms in the denominator is more important when is very large?
The integral diverges.
Which of the two terms in the denominator is more important when ? Which one is more important when is very large?
The integral converges.
What are the “problem 's” for this integral? Get a simple approximation to the integrand near each.
The integral converges.
Further than practice: several ideas at once, or an unfamiliar situation.
We craft a tall, vuvuzela-shaped solid by rotating the line from to about the -axis, where is some constant between 0 and 1.
True or false: No matter how large a constant is, there is some value of that makes a solid with volume larger than .
To find the volume of the solid, cut it into horizontal slices, which are thin circular disks.
The true/false statement is equivalent to saying that the improper integral giving the volume of the solid when diverges to infinity.
false
Review Example 1.12.8 in the
CLP-2 text. Remember the antiderivative of looks very different from the antiderivative of other powers of .
Compare to Example 1.12.14 in the CLP-2 text. You can antidifferentiate with a -substitution.
To evaluate the integral, you can factor the denominator.
Recall . For the other limits, use logarithm rules, and beware of indeterminate forms.
Break up the integral. The absolute values give you a nice even function, so you can replace with if you're careful about the limits of integration.
The integral converges.
Use integration by parts twice to find the antiderivative of , as in Example 1.7.10 of the CLP-2 text. Be careful with your signs — it's easy to make a mistake with all those negatives.
If you're having a hard time taking the limit at the end, review the Squeeze Theorem, Theorem 1.4.17 in the CLP-1 text.
What is the limit of the integrand when ?
The integral converges.
The only “source of impropriety" is the infinite domain of integration. Don't be afraid to be a little creative to make a comparison work.
The integral converges.
Let be the Midpoint Rule approximation for with equal subintervals. Find a value of and a value of such that differs from by at most . Recall that the error introduced when the Midpoint Rule is used with subintervals obeys
where is the maximum absolute value of the second derivative of the integrand and and are the end points of the interval of integration.
There are two things that contribute to your error: using as the upper bound instead of infinity, and using intervals for the approximation.
First, find a so that the error introduced by approximating by is at most . Then, find your .
and will do the job. There are many other correct answers.
Suppose is continuous for all real numbers, and converges.
If is odd, does converge or diverge, or is there not enough information to decide?
If is even, does converge or diverge, or is there not enough information to decide?
Look for a place to use Theorem 1.12.20 of the CLP-2 text.
Examples 1.2.9 and 1.2.10 in the CLP-2 text have nice results about the area under an even/odd curve.
(a) The integral converges. (b) The interval converges.
should be a real number
false
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