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Further methods and applications

13.1 State-space diagrams

5 problems · hints, answers and solutions shown beside each one

Differential equation. Given the differential equation and initial condition

dydt=y2(ya), y(0)=2a\frac{dy}{dt}=y^2(y-a), ~y(0)=2a

where a>0a>0 is a constant, the value of the function y(t)y(t) would

  1. approach y=0y=0;

  2. grow larger with time;

  3. approach y=ay=a;

  4. stay the same;

  5. none of the above.

Answer

(B)

There's a hole in the bucket. Water flows into a bucket at constant rate II. There is a hole in the container. Explain the model

dhdt=Ikh.\frac{dh}{dt}=I-k\sqrt{h}.

Analyze the behaviour predicted. What would the height be after a long time? Is this result always valid, or is an additional assumption needed? (hint: recall Example 11.2.3 in the text.)

Answer

h(t)(I/K)2h(t) \to (I/K)^2

Cubical crystal. A crystal grows inside a medium in a cubical shape with side length xx and volume V.V. The rate of change of the volume is given by

dVdt=kx2(V0V)\frac{dV}{dt} = k x^{2}(V_{0} - V)

where kk and V0V_{0} are positive constants.

  1. Rewrite this as a differential equation for dxdt.\frac{dx}{dt}.

  2. Suppose that the crystal grows from a very small “seed.” Show that its growth rate continually decreases.

  3. What happens to the size of the crystal after a very long time?

  4. What is its volume when xx it is growing at half its initial rate, assuming the initial value of xx is close to 0?

Hint

Use the formula for the volume of a cube, V=x3V=x^3, for (a).

Answer

(a) dxdt=k3(V0x3)\displaystyle \frac{dx}{dt} = \frac{k}{3}(V_{0}-x^{3}); (d) V=12V0\displaystyle V=\frac12 V_{0}.

Logistic growth with proportional harvesting. Consider a fish population of density N(t)N(t) growing at rate g(N)g(N), with harvesting, so that the population satisfies the differential equation

dNdt=g(N)h(N).\frac{dN}{dt}= g(N)-h(N).

Now assume that the growth rate is logistic, so g(N)=rN(KN)Kg(N)= r N \frac{(K - N)}{K} where r,K>0r, K>0 are constant. Assume that the rate of harvesting is proportional to the population size, so that

h(N)=qENh(N) = q E N

where EE, the effort of the fishermen, and qq, the catchability of this type of fish, are positive constants.

Use qualitative methods discussed in this chapter to analyze the behaviour of this equation. Under what conditions does this lead to a sustainable fishery?

Logistic growth with constant number harvesting. Consider the same fish population as in Exercise 4, but this time assume that the rate of harvesting is fixed, regardless of the population
size, so that

h(N)=Hh(N) = H

where HH is a constant number of fish being caught and removed per unit time. Analyze this revised model and compare it to the previous results.

Source

Quetsions in this section are taken from Keshet, Chapter 13.

From the UBC Math 100 open textbook project, © Joel Feldman, Andrew Rechnitzer, Elyse Yeager and others. Licensed CC BY-NC-SA 4.0; this HTML adaptation is released under the same licence. Full attribution.